1. Stating the problem: We need to find the volume of a pentagonal pyramid given the base length $b = 11$ cm, apothem $a = 7.57$ cm, and height $h = 16$ m. 2. Convert height to cm for consistent units: $16 \text{ m} = 1600 \text{ cm}$. 3. Calculate the area of the pentagonal base. The area $A$ of a regular pentagon is $$A = \frac{1}{2} \times \text{Perimeter} \times \text{Apothem}.$$ The perimeter $P = 5 \times b = 5 \times 11 = 55$ cm. Hence, $$A = \frac{1}{2} \times 55 \times 7.57 = 27.5 \times 7.57 = 208.175 \text{ cm}^2.$$ 4. The volume $V$ of a pyramid is $$V = \frac{1}{3} \times A \times h = \frac{1}{3} \times 208.175 \times 1600.$$ Calculate volume: $$V = \frac{1}{3} \times 333080 = 111026.67 \text{ cm}^3.$$ 5. Therefore, the volume of the pentagonal pyramid is approximately $111026.67$ cubic centimeters, or equivalently $111.03$ liters (since 1000 cm³ = 1 liter).