1. The problem states that the perimeter of a regular pentagon is 2 meters. 2. A regular pentagon has 5 equal sides. 3. The perimeter $P$ is the sum of all side lengths: $$P = 5 \times s$$ where $s$ is the length of one side. 4. Given $P = 2$ meters, solve for $s$: $$s = \frac{P}{5} = \frac{2}{5} = 0.4$$ meters. 5. Therefore, each side of the regular pentagon measures 0.4 meters.