1. **State the problem:** We have a parallelogram ABCD with sides labeled as follows: - Side CB = $2y - 4$ - Side DA = $y$ - Side CD = $4x$ - Side BA = $x + 9$ We need to find the values of $x$ and $y$. 2. **Recall properties of parallelograms:** Opposite sides of a parallelogram are equal in length. Therefore: - Side CB = Side DA, so $2y - 4 = y$ - Side CD = Side BA, so $4x = x + 9$ 3. **Solve for $y$:** $$2y - 4 = y$$ Subtract $y$ from both sides: $$2y - y - 4 = 0$$ $$y - 4 = 0$$ Add 4 to both sides: $$y = 4$$ 4. **Solve for $x$:** $$4x = x + 9$$ Subtract $x$ from both sides: $$4x - x = 9$$ $$3x = 9$$ Divide both sides by 3: $$x = 3$$ 5. **Final answers:** $$x = 3$$ $$y = 4$$