1. **State the problem:** We need to construct a parallelogram ABCD where $AB = 7\text{ cm}$, $AD = 5\text{ cm}$, $\angle DAB = 65^\circ$, and $\angle ABC = 105^\circ$.\n\n2. **Understanding:** A parallelogram has opposite sides equal and opposite angles equal. We know $AB$, $AD$, and two angles involving these sides.\n\n3. **Step 1: Draw side AB:** Draw a line segment $AB$ of length 7 cm.\n\n4. **Step 2: Construct angle $\angle DAB = 65^\circ$ at point A:** Using a protractor, draw a ray from point A at $65^\circ$ from $AB$.\n\n5. **Step 3: Locate point D on this ray:** From A along this ray, mark point D such that $AD = 5\text{ cm}$\n\n6. **Step 4: Use the property of parallelogram for side BC:** Since ABCD is a parallelogram, $AB \parallel DC$ and $AD \parallel BC$. Therefore, $BC$ is parallel and equal in length to $AD$ and $DC$ is parallel and equal to $AB$.\n\n7. **Step 5: Determine point C:** Since $BC$ is parallel to $AD$, draw a line from B parallel to AD. Similarly, $DC$ is parallel to AB, so draw a line from D parallel to AB. The intersection of these two lines is point C.\n\n8. **Step 6: Verify $\angle ABC = 105^\circ$:** Check if the angle at B formed by points A-B-C is $105^\circ$. If not, adjust construction as necessary to satisfy all conditions.\n\n9. **Summary:** By following the above steps one can construct parallelogram ABCD with given sides and angles.