Parallelogram Angles 80F709
1. **State the problem:** We have a parallelogram ABCD with angles at vertices A and D labeled as $(x + 40)^\circ$ and $(x - 40)^\circ$ respectively. We need to find the value of $x$.
2. **Recall properties of parallelograms:** Opposite angles in a parallelogram are equal, and adjacent angles are supplementary (sum to $180^\circ$).
3. **Apply the supplementary angle rule:** Since angles A and D are adjacent, their measures add up to $180^\circ$:
$$ (x + 40) + (x - 40) = 180 $$
4. **Simplify the equation:**
$$ x + 40 + x - 40 = 180 $$
$$ 2x = 180 $$
5. **Solve for $x$:**
$$ x = \frac{180}{2} = 90 $$
6. **Conclusion:** The value of $x$ is $90$ degrees.