1. **Stating the problem:** We have parallelogram ABCD with \(\angle DAB = 122^\circ\) and point E on side DC such that \(\angle EBC = 22^\circ\). We need to find: (a) \(\angle LADE\) (b) \(\angle EBLAE\) (c) \(\angle LBAED\) 2. **Recall properties of parallelogram:** Opposite angles are equal and consecutive angles are supplementary. 3. **Calculate \(\angle ABC\):** Since \(\angle DAB = 122^\circ\), \[\angle ABC = 180^\circ - 122^\circ = 58^\circ\] 4. **Triangle \(\triangle EBC\):** Given \(\angle EBC = 22^\circ\) and \(\angle ABC = 58^\circ\), \(\angle EBA = 22^\circ\) implies that \(\angle CBE = 36^\circ\) since \(58^\circ - 22^\circ = 36^\circ\). 5. **Find \(\angle BAE\):** Since E lies on DC, and ABCD is parallelogram, DC is parallel to AB. We can use alternate interior angles or triangle relations to find \(\angle LADE\). 6. **(a) Calculating \(\angle LADE\):** Since \(\angle DAB = 122^\circ\) and point E lies on DC, then \(\angle LADE = 58^\circ\) because interior angles on a straight line sum to 180°, and \(\angle LADE = 180^\circ - 122^\circ = 58^\circ\). 7. **(b) Calculate \(\angle EBLAE\):** This is an angle formed at point B by lines E-B and L-A-E, which likely corresponds to \(\angle EBC = 22^\circ\). Thus, \(\angle EBLAE = 22^\circ\). 8. **(c) Calculate \(\angle LBAED\):** Assuming this is the angle at point B subtended by points L, B, A, E, D as a reflex angle, with given data, this corresponds to \(180^\circ - 58^\circ = 122^\circ\). **Final answers:** (a) \(58^\circ\) (b) \(22^\circ\) (c) \(122^\circ\)