Subjects geometry

Parallelogram Angle C64Bcc

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Parallelogram Angle C64Bcc


1. **Problem Statement:** In parallelogram ABCD, we are given that angle \(\angle DAB = 60^\circ\). We need to find the measure of angle \(\angle C\). 2. **Recall properties of parallelograms:** - Opposite angles in a parallelogram are equal. - Adjacent angles are supplementary, meaning their sum is \(180^\circ\). 3. **Apply the properties:** Since \(\angle DAB = 60^\circ\), the adjacent angle \(\angle ABC\) satisfies: $$\angle DAB + \angle ABC = 180^\circ$$ $$60^\circ + \angle ABC = 180^\circ$$ $$\angle ABC = 180^\circ - 60^\circ = 120^\circ$$ 4. **Find angle C:** Opposite angles are equal, so: $$\angle C = \angle ABC = 120^\circ$$ **Final answer:** $$\boxed{120^\circ}$$