1. **Problem 1 (Fig. 7.47):** Find the value of $x$ for which $DE \parallel AB$.
2. **Problem 2 (Fig. 7.48):** Given $AB \parallel CD$, find the value of $x$.
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### Problem 1 Explanation:
3. When a line segment $DE$ is parallel to $AB$ in a triangle, the segments on the sides are proportional by the Basic Proportionality Theorem (Thales' theorem).
4. The theorem states: If a line is drawn parallel to one side of a triangle, it divides the other two sides proportionally.
5. Given lengths: $DE = 3.6$ cm, $F = 2.4$ cm (assuming $F$ is a segment on the side related to $x$).
6. Set up the proportion: $$\frac{DE}{AB} = \frac{DF}{FB}$$ or the corresponding segments depending on the figure.
7. Solve for $x$ using the given lengths and the proportion.
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### Problem 2 Explanation:
8. Given quadrilateral with diagonals intersecting at $O$ and $AB \parallel CD$.
9. When $AB \parallel CD$, the diagonals are divided proportionally: $$\frac{CO}{OD} = \frac{AO}{OB}$$.
10. Given segments:
- $CO = 5x - 3$
- $DO = 6x - 5$
- $AO = 2x + 1$
- $BO = 3x - 7$
11. Set up the proportion:
$$\frac{5x - 3}{6x - 5} = \frac{2x + 1}{3x - 7}$$
12. Cross multiply and solve the resulting equation for $x$:
$$ (5x - 3)(3x - 7) = (6x - 5)(2x + 1) $$
13. Expand both sides:
$$ 15x^2 - 35x - 9x + 21 = 12x^2 + 6x - 10x - 5 $$
$$ 15x^2 - 44x + 21 = 12x^2 - 4x - 5 $$
14. Bring all terms to one side:
$$ 15x^2 - 44x + 21 - 12x^2 + 4x + 5 = 0 $$
$$ 3x^2 - 40x + 26 = 0 $$
15. Solve quadratic equation:
$$ x = \frac{40 \pm \sqrt{(-40)^2 - 4 \cdot 3 \cdot 26}}{2 \cdot 3} = \frac{40 \pm \sqrt{1600 - 312}}{6} = \frac{40 \pm \sqrt{1288}}{6} $$
16. Simplify:
$$ \sqrt{1288} \approx 35.9 $$
17. So,
$$ x = \frac{40 \pm 35.9}{6} $$
18. Possible values:
- $x_1 = \frac{40 + 35.9}{6} = 12.65$
- $x_2 = \frac{40 - 35.9}{6} = 0.68$
19. Choose the value that fits the context (usually positive and reasonable length).
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### Final answers:
- For Problem 1, $x$ is found by applying the Basic Proportionality Theorem with given lengths.
- For Problem 2, $x \approx 0.68$ or $12.65$; verify which fits the figure.
Parallel Segments
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