1. **State the problem:** Daniel needs to paint the walls and ceiling of a cuboidal hall with dimensions length = 15 m, breadth = 10 m, and height = 7 m. Each can of paint covers 100 m^2. We need to find how many cans of paint are required. 2. **Formula and explanation:** - Surface area to be painted = Area of 4 walls + Area of ceiling - Area of 4 walls = 2 \times height \times (length + breadth) - Area of ceiling = length \times breadth - Total area = 2h(l + b) + lb - Number of cans = \frac{\text{Total area}}{100} 3. **Calculate the area of walls:** $$2 \times 7 \times (15 + 10) = 2 \times 7 \times 25 = 350 \text{ m}^2$$ 4. **Calculate the area of ceiling:** $$15 \times 10 = 150 \text{ m}^2$$ 5. **Calculate total area to be painted:** $$350 + 150 = 500 \text{ m}^2$$ 6. **Calculate number of cans needed:** $$\frac{500}{100} = 5$$ **Final answer:** Daniel needs 5 cans of paint to cover the walls and ceiling of the hall.