Major Arc Dbc
1. **State the problem:** We are given a circle with center $P$ and two diameters $\overline{BD}$ and $\overline{AC}$. We need to find the measure of the major arc $\overset{\frown}{DBC}$ in degrees.
2. **Analyze the given information:**
- $\overline{BD}$ and $\overline{AC}$ are diameters, so they intersect at the center $P$ and divide the circle into four arcs.
- $\angle APB = 19^\circ$ is the angle between radii $PA$ and $PB$.
3. **Understand the geometry:**
- Since $BD$ is a diameter, points $B$ and $D$ lie on opposite ends of the circle.
- Similarly, $AC$ is a diameter, so points $A$ and $C$ lie on opposite ends.
- The angle $\angle APB = 19^\circ$ is the angle between radii $PA$ and $PB$.
4. **Find the measure of minor arc $\overset{\frown}{AB}$:**
- The measure of the central angle $\angle APB$ equals the measure of the minor arc $\overset{\frown}{AB}$.
- Therefore, $m\overset{\frown}{AB} = 19^\circ$.
5. **Find the measure of minor arc $\overset{\frown}{BC}$:**
- Since $BD$ is a diameter, $\overset{\frown}{BC}$ is a quarter of the circle minus $\overset{\frown}{AB}$.
- The circle is $360^\circ$, so each quarter arc is $90^\circ$.
- $m\overset{\frown}{BC} = 90^\circ - 19^\circ = 71^\circ$.
6. **Find the measure of minor arc $\overset{\frown}{CD}$:**
- $CD$ is the other half of the circle opposite $AB$ and $BC$.
- Since $BD$ is a diameter, $\overset{\frown}{CD}$ is $180^\circ$.
7. **Calculate the measure of major arc $\overset{\frown}{DBC}$:**
- Major arc $\overset{\frown}{DBC}$ consists of arcs $\overset{\frown}{DB}$ and $\overset{\frown}{BC}$.
- Since $DB$ is the other half of the circle opposite $BD$, $m\overset{\frown}{DB} = 180^\circ$.
- We already found $m\overset{\frown}{BC} = 71^\circ$.
- Therefore, $m\overset{\frown}{DBC} = 180^\circ + 71^\circ = 251^\circ$.
**Final answer:**
$$m\overset{\frown}{DBC} = 251^\circ$$