1. **State the problem:** Kali has a 6 meter ladder leaning against a tree. The base of the ladder is 2 meters from the tree. We need to find how high the ladder reaches on the tree. 2. **Identify the triangle sides:** The ladder is the hypotenuse $c = 6$ meters. The base (distance from tree to ladder base) is $b = 2$ meters. The height $h$ (how high the ladder reaches) is unknown. 3. **Apply the Pythagorean theorem:** For a right triangle, $$h^2 + b^2 = c^2$$ Substitute known values: $$h^2 + 2^2 = 6^2$$ $$h^2 + 4 = 36$$ 4. **Solve for $h^2$:** $$h^2 = 36 - 4 = 32$$ 5. **Find $h$ by taking the square root:** $$h = \sqrt{32} = \sqrt{16 \times 2} = 4\sqrt{2} \approx 5.656854$$ 6. **Round to the nearest tenth:** $$h \approx 5.7$$ meters **Final answer:** The ladder reaches approximately 5.7 meters high into the tree.