1. Problem: Find the area and perimeter of the L-shaped polygon with vertical sides 10 cm and 8 cm, and horizontal sides 18 cm and 8 cm. 2. Breakdown the L-shape into two rectangles: - Rectangle 1: height 10 cm, width 8 cm - Rectangle 2: height 8 cm, width (18 - 8) = 10 cm 3. Calculate the area of each rectangle: $$\text{Area}_1 = 10 \times 8 = 80 \text{ cm}^2$$ $$\text{Area}_2 = 8 \times 10 = 80 \text{ cm}^2$$ 4. Total area of the L-shape: $$\text{Area} = 80 + 80 = 160 \text{ cm}^2$$ 5. Calculate the perimeter by summing all outer sides: All sides in order (starting from bottom-left corner): - Bottom horizontal: 18 cm - Right vertical (short): 8 cm - Right vertical (long): 10 cm - Top horizontal (short): 8 cm - Left vertical total: 10 + 8 = 18 cm But note overlapping sides are counted only once. So the perimeter is: $$\text{Perimeter} = 18 + 8 + 10 + 8 + 10 = 54 \text{ cm}$$ (We consider the left side as 10 cm and top side as 8 cm for proper closure.) Final answers: - Area = 160 cm² - Perimeter = 54 cm