Isosceles Triangle Angles 826D35
1. **State the problem:** In triangle $\triangle ACD$, sides $AC$ and $AD$ are congruent, so $\triangle ACD$ is isosceles with $AC \cong AD$.
Given:
- $m\angle A = 3x - 4$
- $m\angle C = 5x + 1$
- $m\angle D = 7x - 27$
Find $x$ and the measure of each angle.
2. **Use properties of isosceles triangles:**
- Since $AC \cong AD$, the angles opposite these sides are congruent.
- Therefore, $m\angle C = m\angle D$.
3. **Set up the equation:**
$$5x + 1 = 7x - 27$$
4. **Solve for $x$:**
$$5x + 1 = 7x - 27$$
$$1 + 27 = 7x - 5x$$
$$28 = 2x$$
$$x = 14$$
5. **Find each angle measure by substituting $x=14$:**
- $m\angle A = 3(14) - 4 = 42 - 4 = 38$ degrees
- $m\angle C = 5(14) + 1 = 70 + 1 = 71$ degrees
- $m\angle D = 7(14) - 27 = 98 - 27 = 71$ degrees
6. **Check sum of angles:**
$$m\angle A + m\angle C + m\angle D = 38 + 71 + 71 = 180$$ degrees, which is correct for a triangle.
**Final answers:**
- $x = 14$
- $m\angle A = 38$ degrees
- $m\angle C = 71$ degrees
- $m\angle D = 71$ degrees