1. The problem is to find the sum of the interior angles of a polygon given a value 360, which seems to be related to the sum of exterior angles. 2. Recall that the sum of the exterior angles of any polygon is always $360^\circ$. 3. The sum of the interior angles of a polygon with $n$ sides is given by the formula: $$\text{Sum of interior angles} = 180(n-2)$$ 4. Since the sum of exterior angles is $360^\circ$, this is a constant and does not depend on the number of sides. 5. To find the sum of interior angles, you need to know the number of sides $n$ of the polygon. 6. If you have a polygon with $n$ sides, then the sum of interior angles is: $$180(n-2)$$ 7. For example, if $n=4$ (a quadrilateral), the sum of interior angles is: $$180(4-2) = 180 \times 2 = 360^\circ$$ 8. So, the sum of interior angles is not always 360; it depends on the number of sides. 9. The sum of exterior angles is always 360, which might be the source of confusion. Final answer: The sum of interior angles of a polygon with $n$ sides is $$180(n-2)$$ degrees.