1. We are asked to find the volume of an ice cream cone with radius $r=2$ inches and height $h=6$ inches. 2. The volume $V$ of a cone is given by the formula $$V = \frac{1}{3} \pi r^2 h.$$ 3. Substitute the given values: $$V = \frac{1}{3} \pi (2)^2 (6).$$ 4. Simplify the radius squared: $2^2 = 4$, so $$V = \frac{1}{3} \pi \times 4 \times 6.$$ 5. Multiply inside the numerator: $$4 \times 6 = 24,$$ so $$V = \frac{24}{3} \pi = 8 \pi.$$ 6. The volume of the cone is $$8 \pi \text{ cubic inches}.$$ 7. If approximated numerically, using $\pi \approx 3.1416$, $$V \approx 8 \times 3.1416 = 25.133.$$ Therefore, the cone can hold approximately 25.133 cubic inches of ice cream.