Hall Cost
1. **State the problem:**
We have a cuboid-shaped community hall with dimensions 30 m (length), 15 m (width), and 3 m (height).
We need to find the cost of painting the walls and ceiling and tiling the floor.
2. **Calculate the area to be painted:**
The walls consist of two pairs:
- Two walls of size 30 m × 3 m each
- Two walls of size 15 m × 3 m each
Total wall area = $2 \times (30 \times 3) + 2 \times (15 \times 3) = 2 \times 90 + 2 \times 45 = 180 + 90 = 270$ m²
3. **Calculate the ceiling area:**
Ceiling area is the floor area as well since it's a cuboid:
$30 \times 15 = 450$ m²
4. **Total paint area (walls + ceiling):**
$270 + 450 = 720$ m²
5. **Calculate how many tins of paint are needed:**
Each tin covers 25 m².
Number of tins = $\frac{720}{25} = 28.8$ tins
Since tins can't be bought in fractions, round up to 29 tins.
6. **Calculate paint cost:**
Each tin costs 10.
Total paint cost = $29 \times 10 = 290$
7. **Calculate floor area (for tiles):**
$30 \times 15 = 450$ m²
8. **Calculate tile cost:**
Each tile covers 1 m² and costs 3.
Total tile cost = $450 \times 3 = 1350$
9. **Calculate total cost:**
Total cost = paint cost + tile cost = $290 + 1350 = 1640$
**Final answers:**
- Paint cost: $290$
- Tiles cost: $1350$
- Total cost: $1640$