1. **State the problem:** We have a floor with vertices at J(2,1), K(2,8), L(9,8), and M(9,1) on a coordinate plane. We need to identify the shape and find its perimeter and area. 2. **Find the lengths of the sides:** - Length JK: vertical distance between (2,1) and (2,8) is $8 - 1 = 7$ feet. - Length KL: horizontal distance between (2,8) and (9,8) is $9 - 2 = 7$ feet. - Length LM: vertical distance between (9,8) and (9,1) is $8 - 1 = 7$ feet. - Length MJ: horizontal distance between (9,1) and (2,1) is $9 - 2 = 7$ feet. 3. **Determine the shape:** - All sides are equal in length (7 feet). - Opposite sides are parallel and equal. - Angles are right angles because the sides are aligned with the axes. - Therefore, the shape is a square. 4. **Calculate the perimeter:** - Perimeter $= 4 \times 7 = 28$ feet. 5. **Calculate the area:** - Area $= \text{side}^2 = 7^2 = 49$ square feet. **Final answers:** - Shape: square - Perimeter: 28 feet - Area: 49 square feet