Find Angle A 4C3C10
1. **State the problem:** We need to find the value of $a$ given the angles in a triangle where one angle is $90^\circ$, another is $21^\circ$, and the third is $(2a + 6)^\circ$.
2. **Recall the triangle angle sum rule:** The sum of the interior angles in any triangle is always $180^\circ$.
3. **Set up the equation:** Using the given angles,
$$90 + 21 + (2a + 6) = 180$$
4. **Simplify the equation:**
$$111 + 2a + 6 = 180$$
$$2a + 117 = 180$$
5. **Solve for $a$:**
$$2a = 180 - 117$$
$$2a = 63$$
$$a = \frac{63}{2} = 31.5$$
6. **Conclusion:** The value of $a$ is $31.5$.