1. The problem asks for the surface area of a dome, which is half of a sphere, with radius $r = 57$ metres. 2. The formula for the surface area of a full sphere is $4\pi r^2$. 3. Since the dome is half of the sphere, its surface area is half of that, so: $$\text{Surface area} = \frac{1}{2} \times 4\pi r^2 = 2\pi r^2$$ 4. Substitute $r = 57$ metres into the formula: $$\text{Surface area} = 2 \pi (57)^2 = 2 \pi \times 3249$$ 5. Now calculate the value: $$\text{Surface area} = 2 \pi \times 3249 = 6498 \pi$$ 6. Approximate $\pi \approx 3.1416$: $$\text{Surface area} \approx 6498 \times 3.1416 = 20418.87$$ 7. Therefore, the surface area of the dome is approximately $20418.87$ square metres.