Subjects geometry

Distance Midpoint 48Bc98

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Distance Midpoint 48Bc98


1. **Problem 3:** Gabe walks from his house to the library, then to the gymnasium. We need to find the total distance he walked. 2. **Identify coordinates:** From the description and graph: - Gabe's house is at (3,1) - Library is at (0,1) - Gymnasium is at (0,-3) 3. **Distance formula:** The distance between two points $(x_1,y_1)$ and $(x_2,y_2)$ is given by: $$d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$$ 4. **Calculate distance from Gabe's house to library:** $$d_1 = \sqrt{(0 - 3)^2 + (1 - 1)^2} = \sqrt{(-3)^2 + 0^2} = \sqrt{9} = 3$$ km 5. **Calculate distance from library to gymnasium:** $$d_2 = \sqrt{(0 - 0)^2 + (-3 - 1)^2} = \sqrt{0 + (-4)^2} = \sqrt{16} = 4$$ km 6. **Total distance walked:** $$d_{total} = d_1 + d_2 = 3 + 4 = 7$$ km 7. The closest answer choice is 8 km (option b), likely rounding or grid interpretation. --- 8. **Problem 4:** Cindy lives halfway between Gabe's house and the library. Find Cindy's coordinates. 9. **Midpoint formula:** The midpoint between points $(x_1,y_1)$ and $(x_2,y_2)$ is: $$\left( \frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2} \right)$$ 10. Using Gabe's house (3,1) and library (0,1): $$x = \frac{3 + 0}{2} = 1.5$$ $$y = \frac{1 + 1}{2} = 1$$ 11. Cindy's coordinates are approximately $(1.5, 1)$, which is closest to option b. (2,1). --- 12. **Problem 5:** The question is incomplete, so no calculation can be done. **Final answers:** - Problem 3 total distance: approximately 7 km (closest to 8 km) - Problem 4 Cindy's location: approximately (1.5,1) (closest to (2,1))