Distance Midpoint 48Bc98
1. **Problem 3:** Gabe walks from his house to the library, then to the gymnasium. We need to find the total distance he walked.
2. **Identify coordinates:** From the description and graph:
- Gabe's house is at (3,1)
- Library is at (0,1)
- Gymnasium is at (0,-3)
3. **Distance formula:** The distance between two points $(x_1,y_1)$ and $(x_2,y_2)$ is given by:
$$d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$$
4. **Calculate distance from Gabe's house to library:**
$$d_1 = \sqrt{(0 - 3)^2 + (1 - 1)^2} = \sqrt{(-3)^2 + 0^2} = \sqrt{9} = 3$$ km
5. **Calculate distance from library to gymnasium:**
$$d_2 = \sqrt{(0 - 0)^2 + (-3 - 1)^2} = \sqrt{0 + (-4)^2} = \sqrt{16} = 4$$ km
6. **Total distance walked:**
$$d_{total} = d_1 + d_2 = 3 + 4 = 7$$ km
7. The closest answer choice is 8 km (option b), likely rounding or grid interpretation.
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8. **Problem 4:** Cindy lives halfway between Gabe's house and the library. Find Cindy's coordinates.
9. **Midpoint formula:** The midpoint between points $(x_1,y_1)$ and $(x_2,y_2)$ is:
$$\left( \frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2} \right)$$
10. Using Gabe's house (3,1) and library (0,1):
$$x = \frac{3 + 0}{2} = 1.5$$
$$y = \frac{1 + 1}{2} = 1$$
11. Cindy's coordinates are approximately $(1.5, 1)$, which is closest to option b. (2,1).
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12. **Problem 5:** The question is incomplete, so no calculation can be done.
**Final answers:**
- Problem 3 total distance: approximately 7 km (closest to 8 km)
- Problem 4 Cindy's location: approximately (1.5,1) (closest to (2,1))