Cylinder Surface Area Cf599F
1. **Problem Statement:**
If the height of a cylinder is increased by 15% and the radius of its base is reduced by 10%, find the percentage change in the surface area of the cylinder.
2. **Formula for Surface Area of Cylinder:**
The total surface area $S$ of a cylinder with radius $r$ and height $h$ is given by:
$$S = 2\pi r^2 + 2\pi r h$$
where $2\pi r^2$ is the area of the two circular bases and $2\pi r h$ is the lateral surface area.
3. **Changes in dimensions:**
- New height $h' = h + 0.15h = 1.15h$
- New radius $r' = r - 0.10r = 0.90r$
4. **New surface area $S'$:**
$$S' = 2\pi (r')^2 + 2\pi r' h' = 2\pi (0.90r)^2 + 2\pi (0.90r)(1.15h)$$
$$= 2\pi (0.81r^2) + 2\pi (1.035 r h) = 2\pi r^2 (0.81) + 2\pi r h (1.035)$$
5. **Original surface area $S$:**
$$S = 2\pi r^2 + 2\pi r h$$
6. **Calculate the ratio $\frac{S'}{S}$:**
$$\frac{S'}{S} = \frac{2\pi r^2 (0.81) + 2\pi r h (1.035)}{2\pi r^2 + 2\pi r h} = \frac{0.81 (2\pi r^2) + 1.035 (2\pi r h)}{2\pi r^2 + 2\pi r h}$$
7. **Let $x = \frac{h}{r}$ to simplify:**
$$\frac{S'}{S} = \frac{0.81 (2\pi r^2) + 1.035 (2\pi r^2 x)}{2\pi r^2 + 2\pi r^2 x} = \frac{0.81 + 1.035 x}{1 + x}$$
8. **Interpretation:**
The percentage change depends on $x = \frac{h}{r}$. Without $x$, we cannot find exact percentage change.
9. **Assuming $h = r$ (i.e., $x=1$) for calculation:**
$$\frac{S'}{S} = \frac{0.81 + 1.035}{1 + 1} = \frac{1.845}{2} = 0.9225$$
10. **Percentage change:**
$$\text{Change} = (0.9225 - 1) \times 100 = -7.75\%$$
This means surface area decreases by 7.75% if $h = r$.
11. **Check options:**
Options are (a) 2.5% increase, (b) 3.5% increase, (c) 2.5% decrease, (d) 3.5% decrease.
Since our calculated change is about 7.75% decrease, none exactly matches.
12. **Alternate approach:**
If lateral surface area dominates (height much larger than radius), then:
$$\frac{S'}{S} \approx \frac{1.035}{1} = 1.035$$
which is a 3.5% increase.
If base area dominates (radius much larger than height), then:
$$\frac{S'}{S} \approx 0.81$$
which is a 19% decrease.
13. **Conclusion:**
The problem likely expects the lateral surface area to dominate, so the surface area increases by approximately 3.5%.
**Final answer:** 3.5% increase (option b).