1. **State the problem:** We need to find the area of a compound figure composed of rectangles and a triangle with given side lengths. 2. **Break down the figure:** The figure can be divided into three rectangles and one right triangle. 3. **Identify dimensions:** - Rectangle A (top left): width = 2 ft, height = 3 ft - Rectangle B (middle left): width = 2 ft, height = 2 ft - Rectangle C (bottom right): width = 7 ft, height = 3 ft - Triangle (top right): base = 2 ft (difference between 9 ft and 7 ft), height = 2 ft 4. **Calculate areas:** - Area of Rectangle A = width × height = $2 \times 3 = 6$ sq ft - Area of Rectangle B = $2 \times 2 = 4$ sq ft - Area of Rectangle C = $7 \times 3 = 21$ sq ft - Area of Triangle = $\frac{1}{2} \times base \times height = \frac{1}{2} \times 2 \times 2 = 2$ sq ft 5. **Sum all areas:** $$6 + 4 + 21 + 2 = 33$$ sq ft 6. **Final answer:** The total area of the figure is **33 square feet**.