1. The problem states that A and B represent the minute and hour hands of a clock initially at 12 and 3 respectively. 2. The initial angle between A (minute hand at 12) and B (hour hand at 3) is $90^\circ$ because each hour mark on a clock represents $30^\circ$ and 3 hours difference means $3 \times 30^\circ = 90^\circ$. 3. A moves to a position $54^\circ$ from B's initial position (which was at 3 o'clock). 4. The current angle between A and B is therefore $54^\circ$. 5. The difference between the initial and current angle is calculated as: $$\text{Difference} = |90^\circ - 54^\circ| = 36^\circ$$ 6. Hence, the difference between the initial and current angle between A and B is $36$ degrees. **Final answer:** $36$ degrees.