1. First, let's restate the problem in English:\nWe need to find the minimum length of iron rod needed to make 100 window grilles shaped as circular sectors (juring) with radius $14$ cm and central angle $60^\circ$.\n\n2. Calculate the length of the arc of one sector. The arc length $L$ of a sector is given by:\n$$L = r \times \theta$$\nwhere $r = 14$ cm and $\theta$ is in radians. Convert $60^\circ$ to radians:\n$$\theta = 60^\circ \times \frac{\pi}{180^\circ} = \frac{\pi}{3}$$\nSo,\n$$L = 14 \times \frac{\pi}{3} = \frac{14\pi}{3} \text{ cm}$$\n\n3. Calculate the perimeter (length of iron rod needed) for one sector. It consists of two radii plus the arc length:\n$$P = 2r + L = 2 \times 14 + \frac{14\pi}{3} = 28 + \frac{14\pi}{3} \text{ cm}$$\n\n4. For 100 identical sectors, the total length $T$ is:\n$$T = 100 \times P = 100 \times \left(28 + \frac{14\pi}{3} \right) = 2800 + \frac{1400\pi}{3} \text{ cm}$$\n\n5. To get a decimal approximation:\n$$\pi \approx 3.1416$$\n$$\frac{1400\pi}{3} \approx \frac{1400 \times 3.1416}{3} \approx 1466.08 \text{ cm}$$\nThus,\n$$T \approx 2800 + 1466.08 = 4266.08 \text{ cm}$$\nOr about $42.66$ meters.\n\n**Final answer:** The minimum length of iron rod needed to make 100 grilles is approximately 4266.08 cm or 42.66 meters.