1. **Problem:** A rectangular field with length 5 m and width 8 m has a cement path 2 m wide around it. Find the area of the cement path. 2. **Step 1:** Calculate the dimensions of the field including the cement path. - Length including the path = $5 + 2 \times 2 = 9$ m - Width including the path = $8 + 2 \times 2 = 12$ m 3. **Step 2:** Find the area of the larger rectangle including path. $$\text{Area}_{\text{larger}} = 9 \times 12 = 108 \text{ m}^2$$ 4. **Step 3:** Find the area of the original field. $$\text{Area}_{\text{field}} = 5 \times 8 = 40 \text{ m}^2$$ 5. **Step 4:** Find the area of the cement path by subtracting the field area from the larger area. $$\text{Area}_{\text{path}} = 108 - 40 = 68 \text{ m}^2$$ **Answer:** The area of the cement path is $68$ square meters.