1. **State the problem:** We have a large shape made of four trapeziums and one rectangle in the center. The rectangle has dimensions 13 cm by 8 cm. The entire shape has a height of 14 cm and a width of 19 cm. We need to find the area of the unshaded trapezium on the right. 2. **Identify dimensions:** - Height of the whole shape: $14$ cm - Height of the rectangle: $8$ cm - Width of the rectangle: $13$ cm - Width of the whole shape: $19$ cm 3. **Calculate the height of the trapeziums:** The trapeziums surround the rectangle, so their height is the difference between the total height and the rectangle height: $$14 - 8 = 6 \text{ cm}$$ 4. **Calculate the width of the trapeziums on the sides:** The total width is $19$ cm, and the rectangle width is $13$ cm, so the combined width of the two trapeziums on the left and right is: $$19 - 13 = 6 \text{ cm}$$ Since there are two trapeziums on the sides, each has a width of: $$\frac{6}{2} = 3 \text{ cm}$$ 5. **Dimensions of the unshaded right trapezium:** - Height: $14$ cm (full height) - Top base: $8$ cm (height of rectangle) - Bottom base: $14$ cm (full height) - Width (distance between bases): $3$ cm 6. **Calculate the area of the trapezium:** The area formula for a trapezium is: $$\text{Area} = \frac{(a + b)}{2} \times h$$ where $a$ and $b$ are the lengths of the parallel sides and $h$ is the height (distance between them). Here, the parallel sides are the top and bottom edges of the trapezium, which correspond to the heights of the rectangle and the full shape, so: $$a = 8, \quad b = 14, \quad h = 3$$ Calculate the area: $$\text{Area} = \frac{(8 + 14)}{2} \times 3 = \frac{22}{2} \times 3 = 11 \times 3 = 33$$ 7. **Final answer:** The area of the unshaded trapezium is **33 cm²**.