1. **Problem Statement:** Find the area difference between a square of side length 7 units and a quarter circle of radius 7 units inscribed inside it. 2. **Formulae Used:** - Area of square: $A_{square} = s^2$ - Area of sector (quarter circle): $A_{sector} = \frac{\theta}{360} \times \pi r^2$ 3. **Calculations:** - Side length of square $s = 7$ - Area of square: $A_{square} = 7 \times 7 = 49$ - Angle of sector $\theta = 90^\circ$ - Radius of sector $r = 7$ - Area of sector: $$A_{sector} = \frac{90}{360} \times \pi \times 7^2 = \frac{1}{4} \times \pi \times 49 = 12.25\pi$$ - Approximate value: $12.25 \times 3.1416 \approx 38.48$ 4. **Area difference:** - $A_{difference} = A_{sector} - A_{square} = 38.48 - 49 = -10.52$ 5. **Interpretation:** The quarter circle area is smaller than the square area by approximately $10.52$ square units. **Final answer:** The difference in area is approximately $10.52$ square units, with the square being larger.