Subjects geometry

Area Compound Rectangles F72Abd

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Area Compound Rectangles F72Abd


1. **Problem Statement:** Calculate the area of a compound figure made up of five rectangles with given dimensions. 2. **Approach:** The total area of the compound figure is the sum of the areas of the individual rectangles. 3. **Identify Rectangles and Dimensions:** - Bottom rectangle: width = 15 m, height = 6 m - Left rectangle above bottom: width = 8 m, height = 5 m - Middle lower rectangle above bottom: width = 5 m, height = 5 m - Top small rectangle above middle: width = 2 m, height = 2 m - Right rectangle height total = 13 m, so height above bottom rectangle = 13 m - 6 m = 7 m (this is the combined height of the two stacked rectangles on the right side) 4. **Calculate Areas:** - Area of bottom rectangle: $$15 \times 6 = 90$$ - Area of left rectangle: $$8 \times 5 = 40$$ - Area of middle lower rectangle: $$5 \times 5 = 25$$ - Area of top small rectangle: $$2 \times 2 = 4$$ 5. **Check for Overlaps:** The top small rectangle is part of the middle right stack, so the middle lower rectangle and top small rectangle are stacked, their combined height is $$5 + 2 = 7$$ which matches the right side height above bottom. 6. **Sum of all areas:** $$90 + 40 + 25 + 4 = 159$$ 7. **Final Answer:** The area of the compound figure is **159 square meters**.