1. **State the problem:** We need to find the area of a polygon composed of a rectangle and a triangle on top. The rectangle has a height of 18 cm, and the triangle has a height of 7 cm. Both share the same base width of 7 cm. 2. **Calculate the area of the rectangle:** The area of a rectangle is given by $$\text{Area} = \text{base} \times \text{height}$$. Here, base = 7 cm and height = 18 cm. $$\text{Area}_{rectangle} = 7 \times 18 = 126 \text{ cm}^2$$ 3. **Calculate the area of the triangle:** The area of a triangle is given by $$\text{Area} = \frac{1}{2} \times \text{base} \times \text{height}$$. Here, base = 7 cm and height = 7 cm. $$\text{Area}_{triangle} = \frac{1}{2} \times 7 \times 7 = \frac{49}{2} = 24.5 \text{ cm}^2$$ 4. **Find the total area of the shape:** Add the areas of the rectangle and the triangle. $$\text{Total Area} = 126 + 24.5 = 150.5 \text{ cm}^2$$ **Final answer:** The area of the shape is $$150.5 \text{ cm}^2$$.