1. Problem 3 shows a right triangle with base 8 cm and height 3 cm inside it. Calculate the area using the formula for the area of a triangle: $$\text{Area} = \frac{1}{2} \times \text{base} \times \text{height}$$ Area $= \frac{1}{2} \times 8 \times 3 = 12$ cm² 2. Problem 4 shows a trapezoid with parallel sides 11 cm and 10 cm, height 3 cm. Use the trapezoid area formula: $$\text{Area} = \frac{1}{2} \times (\text{base}_1 + \text{base}_2) \times \text{height}$$ Area $= \frac{1}{2} \times (11 + 10) \times 3 = \frac{1}{2} \times 21 \times 3 = 31.5$ cm² 3. Problem 5 is a triangle with base 8 cm and height 3 cm. Area $= \frac{1}{2} \times 8 \times 3 = 12$ cm² 4. Problem 6 is a rectangle with length 9 cm and width 7 cm. Area $= 9 \times 7 = 63$ cm² 5. Problem 7 is an isosceles triangle with base 12 cm but height not given, so area cannot be computed without height. 6. Problem 8 is a rectangle with length 11 cm and width 5 cm. Area $= 11 \times 5 = 55$ cm² Final answers: 3. Area = 12 cm² 4. Area = 31.5 cm² 5. Area = 12 cm² 6. Area = 63 cm² 7. Area = unknown (height missing) 8. Area = 55 cm²