1. **State the problem:** Find the area of the irregular polygon shaped like an arrow using the given side lengths. 2. **Approach:** The polygon can be divided into three rectangles. We will find the area of each rectangle and then sum them. 3. **Identify rectangles and their dimensions:** - Rectangle A (top rectangle): width = 11 in, height = 2 in - Rectangle B (middle rectangle): width = 3 in, height = 4 in - Rectangle C (bottom rectangle): width = 8 in, height = 3 in 4. **Calculate areas:** - Area of Rectangle A = width × height = $11 \times 2 = 22$ square inches - Area of Rectangle B = $3 \times 4 = 12$ square inches - Area of Rectangle C = $8 \times 3 = 24$ square inches 5. **Sum the areas:** $$\text{Total area} = 22 + 12 + 24 = 58$$ square inches 6. **Final answer:** The area of the figure is **58** square inches.