1. **Problem statement:** We are given a circle with diameters AD and CE intersecting at center P. We need to find the measure of the minor arc AB in degrees. 2. **Key information:** - AD and CE are diameters, so each subtends a 180° arc. - Angle PAB is 38°. - Angle PDE is 93°. 3. **Recall the theorem:** The measure of an inscribed angle is half the measure of its intercepted arc. 4. **Analyze angle PAB:** - Angle PAB is formed by points P, A, and B. - Since P is the center, angle PAB is a central angle or related to the arc AB. 5. **Since AD is a diameter, arc AB is part of the semicircle from A to D.** 6. **Using the inscribed angle theorem:** - The inscribed angle subtending arc AB is half the measure of arc AB. - Given angle PAB = 38°, the arc AB measure is twice that: $$\text{arc } AB = 2 \times 38 = 76^\circ$$ 7. **Final answer:** The measure of minor arc AB is 76 degrees.