Angle Value 6D7Cb1
1. **Problem Statement:** We have two parallel lines $x \parallel y$ and a transversal intersecting them, creating angles $a^\circ$, $b^\circ$, and $c^\circ$. We need to find the value of angle $a$.
2. **Key Concept:** When a transversal crosses two parallel lines, corresponding angles are equal, and alternate interior angles are equal. Also, angles on a straight line sum to $180^\circ$.
3. **Step 1:** Identify relationships. Since $x \parallel y$, angle $b^\circ$ and angle $c^\circ$ are corresponding angles, so $b = c$.
4. **Step 2:** At the intersection with line $x$, angles $a^\circ$ and $b^\circ$ are supplementary because they form a straight line. So,
$$a + b = 180$$
5. **Step 3:** Substitute $b = c$ into the equation:
$$a + c = 180$$
6. **Step 4:** Solve for $a$:
$$a = 180 - c$$
**Final answer:**
$$\boxed{a = 180 - c}$$