Angle Problems 04625D
1. **Problem 8:** \(\angle A\) is obtuse and \(\angle A = (x + 20)^\circ\). Find the limits of \(x\).
- An obtuse angle is greater than 90° and less than 180°.
- So, \(90 < x + 20 < 180\).
- Subtract 20 from all parts: \(90 - 20 < x < 180 - 20\).
- Simplify: \(70 < x < 160\).
**Answer:** \(x\) must satisfy \(70 < x < 160\).
2. **Problem 9:** Find the complement and supplement of each angle.
- Complement of an angle \(\theta\) is \(90^\circ - \theta\).
- Supplement of an angle \(\theta\) is \(180^\circ - \theta\).
**a) For 60°:**
- Complement: \(90 - 60 = 30^\circ\)
- Supplement: \(180 - 60 = 120^\circ\)
**b) For \((x + 10)^\circ\):**
- Complement: \(90 - (x + 10) = 80 - x\)
- Supplement: \(180 - (x + 10) = 170 - x\)
3. **Problem 10:** The supplement of an angle is 40 more than six times the complement. Find the angle.
- Let the angle be \(\theta\).
- Complement: \(90 - \theta\)
- Supplement: \(180 - \theta\)
Given: \(180 - \theta = 6(90 - \theta) + 40\)
Step 1: Expand right side:
$$180 - \theta = 540 - 6\theta + 40$$
Step 2: Simplify right side:
$$180 - \theta = 580 - 6\theta$$
Step 3: Add \(6\theta\) to both sides:
$$180 + 5\theta = 580$$
Step 4: Subtract 180 from both sides:
$$5\theta = 400$$
Step 5: Divide both sides by 5:
$$\theta = 80$$
**Answer:** The angle is \(80^\circ\).