1. The problem involves finding unknown angles at points q, f, and b based on given angles around those points. 2. For point q, the sum of angles around a point is 360°. Given two angles 135° and 105°, the unknown angle $\angle q$ is calculated as: $$\angle q = 360^\circ - (135^\circ + 105^\circ)$$ $$\angle q = 360^\circ - 240^\circ = 120^\circ$$ 3. For point f, with three known angles 68°, 63°, and 141°, the unknown angle $\angle f$ is: $$\angle f = 360^\circ - (68^\circ + 63^\circ + 141^\circ)$$ $$\angle f = 360^\circ - 272^\circ = 88^\circ$$ 4. For point b, the problem states a straight line AB intersected by line CD at point b, with an angle of 145° between extension towards C and b. Since angles on a straight line sum to 180°, the unknown angle $\angle b$ is: $$\angle b = 180^\circ - 145^\circ = 35^\circ$$ 5. Final answers: - $\angle q = 120^\circ$ - $\angle f = 88^\circ$ - $\angle b = 35^\circ$