1. **Bisect angle MNO = 50° with NO = 5 cm** Step 1: Draw the angle MNO with vertex at N and side NO measuring 5 cm. Step 2: Place the compass point at vertex N and draw an arc that intersects both sides NM and NO of the angle. Step 3: Label the intersection points of the arc with NM and NO as A and B respectively. Step 4: Without changing the compass width, place the compass point at A and draw an arc inside the angle. Step 5: Repeat the same from point B, creating an intersection point C of the two arcs inside the angle. Step 6: Draw a straight line from vertex N through point C. This line bisects the angle MNO into two equal 25° angles. 2. **Perpendicular bisector of segment XY where |XY| = 8 cm, name the center P, measure XP** Step 1: Draw segment XY with length 8 cm. Step 2: Place the compass point at X and draw an arc above and below the segment with radius more than half of XY (e.g., 5 cm). Step 3: Without changing the compass width, place the compass point at Y and draw two arcs intersecting the previous arcs above and below the segment. Step 4: Label the intersection points of the arcs as points Q and R. Step 5: Draw a straight line through points Q and R. This line is the perpendicular bisector of XY. Step 6: Label the intersection of the perpendicular bisector and XY as point P. This is the midpoint of XY. Step 7: Since XY = 8 cm, XP = 4 cm (half of XY). **Final answers:** - The bisector of angle MNO divides the 50° angle into two 25° angles. - The perpendicular bisector of XY intersects XY at point P, the midpoint, with XP = 4 cm.