1. The problem involves applying the Acute Triangle Inequality Theorem to triangles ABC and JKL. 2. For triangle JKL, the sides are given as J=3, K=4, L=3. 3. Check if side 42 (assumed length 4) is less than the sum of the other two sides: 32 + 32 (assumed lengths 3 + 3). Calculate: $3 + 3 = 6$. Compare: $4 < 6$ is true. 4. Therefore, triangle JKL satisfies the triangle inequality, and it is an acute triangle. 5. For triangle ABC, sides are A=4, B=3, C=5. 6. Check if side 52 (assumed length 5) is less than the sum of the other two sides: 32 + 42 (3 + 4). Calculate: $3 + 4 = 7$. Compare: $5 < 7$ is true. 7. Applying the same method, triangle ABC also satisfies the triangle inequality, so it is an acute triangle. Final answers: - 42 is less than 32 + 32. - Therefore, triangle JKL is acute. - 52 is less than 32 + 42. - Therefore, triangle ABC is acute.