1. **Stating the problem:** A man has hemophilia, which is an X-linked recessive trait, and his wife is homozygous for the normal allele. We need to determine the genetic outcomes for their children. 2. **Understanding the genetics:** Hemophilia is caused by a recessive allele on the X chromosome. Males have one X and one Y chromosome (XY), females have two X chromosomes (XX). 3. **Parental genotypes:** - Man with hemophilia: X^hY (X chromosome with hemophilia allele, Y chromosome normal) - Woman homozygous normal: X^NX^N (both X chromosomes normal) 4. **Possible gametes:** - Man produces X^h or Y - Woman produces X^N only (since homozygous normal) 5. **Offspring genotypes:** - Sons: inherit Y from father and X^N from mother → X^NY (normal, not hemophilic) - Daughters: inherit X^h from father and X^N from mother → X^NX^h (carriers, not hemophilic because normal allele is dominant) 6. **Conclusion:** - All daughters will be carriers (have one normal and one hemophilia allele but do not express the disease) - All sons will be normal (no hemophilia allele) **Answer:** Option 5. all daughters will be carriers.