1. **State the problem:** Benito borrowed 35000 on February 24 at 15% simple interest. We need to find how much interest he pays on October 30 of the same year. 2. **Formula for simple interest:** $$I = P \times r \times t$$ where $I$ is the interest, $P$ is the principal amount, $r$ is the annual interest rate (in decimal), and $t$ is the time in years. 3. **Calculate the time $t$:** From February 24 to October 30, count the number of days: - February 24 to February 28: 4 days - March: 31 days - April: 30 days - May: 31 days - June: 30 days - July: 31 days - August: 31 days - September: 30 days - October 1 to October 30: 30 days Total days = 4 + 31 + 30 + 31 + 30 + 31 + 31 + 30 + 30 = 248 days Convert days to years: $$t = \frac{248}{365} \approx 0.6795$$ 4. **Convert interest rate to decimal:** $$r = \frac{15}{100} = 0.15$$ 5. **Calculate interest:** $$I = 35000 \times 0.15 \times 0.6795 = 3567.38$$ 6. **Answer:** Benito pays approximately 3567.38 in interest on October 30 of the same year.