1. **State the problem:** We need to solve part (b) of the problem involving simple interest. 2. **Recall the formula for simple interest:** $$I = P \times r \times t$$ where $I$ is the interest, $P$ is the principal amount, $r$ is the annual interest rate (in decimal), and $t$ is the time in years. 3. **Part (b)(i): Find the total amount received by Nipun who deposited 120000 rupees for 2 years at 18% simple annual interest.** - Principal $P = 120000$ - Rate $r = 18\% = 0.18$ - Time $t = 2$ years Calculate interest: $$I = 120000 \times 0.18 \times 2 = 43200$$ Total amount received $A$ is principal plus interest: $$A = P + I = 120000 + 43200 = 163200$$ 4. **Part (b)(ii): Find how long it takes to receive 108000 rupees as interest at 18% simple annual interest with principal 120000.** - Interest $I = 108000$ - Principal $P = 120000$ - Rate $r = 0.18$ Use the formula and solve for $t$: $$t = \frac{I}{P \times r} = \frac{108000}{120000 \times 0.18} = \frac{108000}{21600} = 5$$ So, it takes 5 years to receive 108000 rupees as interest. **Final answers:** - (b)(i) Total amount received = 163200 rupees - (b)(ii) Time to receive 108000 rupees interest = 5 years