1. **State the problem:** Jose invested 79000 in an account with an interest rate of 6.8% compounded quarterly. We want to find the amount in the account after 9 years. 2. **Formula used:** The formula for compound interest is $$A = P \left(1 + \frac{r}{n}\right)^{nt}$$ where: - $A$ is the amount after time $t$, - $P$ is the principal (initial amount), - $r$ is the annual interest rate (decimal), - $n$ is the number of times interest is compounded per year, - $t$ is the time in years. 3. **Identify values:** - $P = 79000$ - $r = 0.068$ (6.8% as decimal) - $n = 4$ (quarterly compounding) - $t = 9$ 4. **Calculate:** $$A = 79000 \left(1 + \frac{0.068}{4}\right)^{4 \times 9} = 79000 \left(1 + 0.017\right)^{36} = 79000 \times (1.017)^{36}$$ 5. **Evaluate power:** Calculate $(1.017)^{36} \approx 1.8111$ 6. **Final amount:** $$A \approx 79000 \times 1.8111 = 142075.9$$ Rounded to the nearest dollar, the amount is **142076**. **Answer:** After 9 years, Jose will have approximately 142076 in the account.