1. **Problem Statement:** Determine the voltage $V_{CB}$ in the given silicon transistor circuit with $\beta = 150$. The circuit has $V_{BB} = 5V$, $V_{CC} = 10V$, $R_B = 10k\Omega$, and $R_C = 100\Omega$. The emitter is grounded. 2. **Known facts and formulas:** - For silicon transistors, the base-emitter voltage $V_{BE} \approx 0.7V$. - Current gain $\beta = \frac{I_C}{I_B} = 150$. - $V_{CB} = V_C - V_B$. 3. **Find base current $I_B$:** Base voltage $V_B = V_{BB} - I_B R_B - V_{BE}$. Assuming $V_B$ is approximately $V_{BB} - V_{BE}$ since $I_B R_B$ is small initially, but we will calculate precisely. 4. **Calculate $I_B$ using KVL in base loop:** $$5V = I_B \times 10,000\Omega + 0.7V$$ $$I_B = \frac{5V - 0.7V}{10,000\Omega} = \frac{4.3V}{10,000\Omega} = 0.00043A = 0.43mA$$ 5. **Calculate collector current $I_C$:** $$I_C = \beta I_B = 150 \times 0.00043A = 0.0645A = 64.5mA$$ 6. **Calculate collector voltage $V_C$ using KVL in collector loop:** $$V_{CC} = I_C R_C + V_C$$ $$V_C = V_{CC} - I_C R_C = 10V - (0.0645A \times 100\Omega) = 10V - 6.45V = 3.55V$$ 7. **Calculate base voltage $V_B$ precisely:** $$V_B = V_{BB} - I_B R_B = 5V - (0.00043A \times 10,000\Omega) = 5V - 4.3V = 0.7V$$ 8. **Calculate $V_{CB}$:** $$V_{CB} = V_C - V_B = 3.55V - 0.7V = 2.85V$$ **Final answer:** $V_{CB} = 2.85V$