1. **Problem Statement:** Given an operational amplifier (op amp) circuit with resistors $R_1 = 2\,K\Omega$ and $R_2 = 4\,K\Omega$, and an input voltage $V_1 = 2\,V$. The op amp is configured as an inverting amplifier. 2. **Part (a): Is this an inverting op amp?** - In an inverting op amp, the input signal is applied to the inverting input through $R_1$, and $R_2$ is connected from the output to the inverting input. - The non-inverting input is grounded. - This matches the given description, so the answer is **TRUE**. 3. **Part (b): Input resistance of the op amp** - The input resistance seen by the source is simply $R_1$ because the input voltage is applied through $R_1$ to the inverting input. - Therefore, input resistance $R_{in} = R_1 = 2\,K\Omega = 2000\,\Omega$. 4. **Part (c): Input current of the op amp** - The input current $I_{in}$ flows through $R_1$. - Since the op amp input draws negligible current, $I_{in} = \frac{V_1 - V_-}{R_1}$. - The inverting input $V_-$ is at virtual ground (0 V) because the non-inverting input is grounded and the op amp has high gain. - So, $I_{in} = \frac{2 - 0}{2000} = 0.001\,A = 1\,mA$. 5. **Part (d): Output voltage of the op amp** - The gain of an inverting amplifier is $A_v = -\frac{R_2}{R_1}$. - Calculate gain: $A_v = -\frac{4000}{2000} = -2$. - Output voltage $V_0 = A_v \times V_1 = -2 \times 2 = -4\,V$. **Final answers:** - (a) TRUE - (b) $2000\,\Omega$ - (c) $1\,mA$ - (d) $-4\,V$