1. **State the problem:** We want to limit the current through a 50 ohm resistor to 10 A when connected to a 600 V power source by adding an auxiliary resistor. 2. **Identify known values:** Voltage, $V = 600$ V Desired current, $I = 10$ A Resistance of resistor, $R_1 = 50 \ \Omega$ 3. **Calculate total resistance needed to achieve 10 A current:** Using Ohm's law, $V = IR$ so total resistance $R_{total} = \frac{V}{I} = \frac{600}{10} = 60 \ \Omega$ 4. **Determine how to add the auxiliary resistor $R_2$ to get total resistance $R_{total}$:** Since we want to limit current, adding resistance in series is required. 5. **Calculate the auxiliary resistor value:** $$R_2 = R_{total} - R_1 = 60 - 50 = 10 \ \Omega$$ 6. **Conclusion:** Connect the auxiliary resistor in series with the 50 ohm resistor. The auxiliary resistor should have resistance 10 ohms. **Final answer:** Auxiliary resistor = 10 ohms connected in series.