1. **State the problem:** We need to find the voltage $V$ in an electronic circuit given the current $C = 6 - j$ and the impedance $J = 4 + 3j$. The formula to use is $V = C \times J$. 2. **Recall the formula and rules:** Voltage $V$ is the product of current $C$ and impedance $J$. When multiplying complex numbers, use the distributive property and remember that $j^2 = -1$. 3. **Calculate the product:** $$V = (6 - j)(4 + 3j)$$ Multiply terms: $$= 6 \times 4 + 6 \times 3j - j \times 4 - j \times 3j$$ $$= 24 + 18j - 4j - 3j^2$$ 4. **Simplify:** Combine like terms: $$24 + (18j - 4j) - 3j^2 = 24 + 14j - 3j^2$$ Since $j^2 = -1$: $$24 + 14j - 3(-1) = 24 + 14j + 3 = 27 + 14j$$ 5. **Final answer:** The voltage is $V = 27 + 14j$. This matches option A).