1. **Problem 2:** Calculate the input power of a DC machine taking 18.6 amperes from a 220 volt supply. 2. **Formula:** Input power $P = V \times I$ where $V$ is voltage and $I$ is current. 3. **Calculation:** $$P = 220 \times 18.6 = 4092 \text{ watts}$$ 4. **Explanation:** The input power is the product of voltage and current, which gives the power in watts. 5. **Problem 3:** Complete the table with missing values for power ($P$), current ($I$), and voltage ($V$). 6. **Formula:** Power $P = V \times I$. 7. **Calculations:** - For $P=500$, $V=500$, find $I$: $$I = \frac{P}{V} = \frac{500}{500} = 1$$ - For $P$ missing, $I=75$, $V$ missing: Use $P = V \times I$; since $P$ and $V$ missing, cannot solve directly. - For $P=3000$, $I=0.25$, find $V$: $$V = \frac{P}{I} = \frac{3000}{0.25} = 12000$$ - For $P=1000$, $I=13.5$, $V=220$ (given), check consistency: $$P = 220 \times 13.5 = 2970 \neq 1000$$ So $P$ likely incorrect or incomplete. - For $P=1000$, $I=10$, $V=110$ (given), check: $$P = 110 \times 10 = 1100$$ - For $P=750$, $I$ missing, $V=240$, find $I$: $$I = \frac{750}{240} = 3.125$$ 8. **Completed table:** | P | 6000 | 500 | ? | 3000 | 1000 | ? | 750 | 1000 | |------|------|-----|---|------|------|---|-----|------| | I | 3 | 1 | 75| 0.25 | 13.5 | 25|3.125| 10 | | V | 120 | 500 | ? | 150 | 220 | ? | 240 | 110 | 9. **Problem 4:** Calculate voltage drop in a resistor with power absorbed 9000 W and current 63 A. 10. **Formula:** Voltage drop $V = \frac{P}{I}$. 11. **Calculation:** $$V = \frac{9000}{63} = 142.86 \text{ volts}$$ 12. **Explanation:** Voltage drop is power divided by current, giving volts. **Final answers:** - Input power = 4092 watts - Completed table values as above - Voltage drop = 142.86 volts