1. The user requests 30% wrong answers for an 80-mark math paper. 2. Calculate 30% of 80 marks: $$0.30 \times 80 = 24$$ marks should be wrong. 3. This means 24 marks will be answered incorrectly, and the remaining 56 marks will be correct. 4. To provide 30% wrong answers, ensure that the total marks of incorrect answers sum to 24. 5. The rest of the answers should be correct to total 80 marks. 6. This approach balances the paper with 30% incorrect and 70% correct answers as requested.