Average Marginal Product 6C947B
1. **Problem Statement:**
Calculate the Average Product of Labor (AP_L) and Marginal Product of Labor (MP_L) from the given Total Product (TP) data.
2. **Formulas:**
- Average Product of Labor: $$AP_L = \frac{TP}{L}$$ where $L$ is units of labor and $TP$ is total product.
- Marginal Product of Labor: $$MP_L = TP_L - TP_{L-1}$$ which is the change in total product when labor increases by one unit.
3. **Calculations:**
- For $L=1$: $$AP_1 = \frac{5}{1} = 5$$, $$MP_1 = 5 - 0 = 5$$
- For $L=2$: $$AP_2 = \frac{12}{2} = 6$$, $$MP_2 = 12 - 5 = 7$$
- For $L=3$: $$AP_3 = \frac{21}{3} = 7$$, $$MP_3 = 21 - 12 = 9$$
- For $L=4$: $$AP_4 = \frac{36}{4} = 9$$, $$MP_4 = 36 - 21 = 15$$
- For $L=5$: $$AP_5 = \frac{50}{5} = 10$$, $$MP_5 = 50 - 36 = 14$$
- For $L=6$: $$AP_6 = \frac{66}{6} = 11$$, $$MP_6 = 66 - 50 = 16$$
- For $L=7$: $$AP_7 = \frac{66}{7} \approx 9.43$$, $$MP_7 = 66 - 66 = 0$$
- For $L=8$: $$AP_8 = \frac{56}{8} = 7$$, $$MP_8 = 56 - 66 = -10$$
4. **Explanation:**
- Average product measures output per unit of labor.
- Marginal product measures the additional output from one more unit of labor.
- Notice MP peaks at $L=6$ and then declines, becoming negative at $L=8$, indicating diminishing returns.
5. **Final Table:**
| L | TP | AP_L | MP_L |
|---|----|------|------|
| 0 | 0 | - | - |
| 1 | 5 | 5 | 5 |
| 2 | 12 | 6 | 7 |
| 3 | 21 | 7 | 9 |
| 4 | 36 | 9 | 15 |
| 5 | 50 | 10 | 14 |
| 6 | 66 | 11 | 16 |
| 7 | 66 | 9.43 | 0 |
| 8 | 56 | 7 | -10 |