1. Stating the problem: We want to simplify the expression $ (A+B+C)(A+B+C)(A+B+C) $ using logic gate laws. 2. First, note that $ (A+B+C)(A+B+C)(A+B+C) $ is equivalent to $ (A+B+C)^3 $ in Boolean algebra. 3. In Boolean algebra, the OR operation $+ $ is idempotent, meaning that $ X + X = X $. Similarly, for AND, $ XX = X $. 4. Since $ A+B+C $ ORed with itself any number of times remains $ A+B+C $, then $ (A+B+C)^3 = A+B+C $. 5. Therefore, the simplified form of $ (A+B+C)(A+B+C)(A+B+C) $ is $ A+B+C $. Final answer: $ A+B+C $