Boolean Bcd Addition
1. **Write the SPOS Boolean logic expression for** $f(A,B,C,D) = \Sigma m(0,2,5,7,8,10,13,15)$.
To find the Sum of Products (SOP) form, list minterms corresponding to the decimal indices:
$$m_0 = \overline{A}\overline{B}\overline{C}\overline{D},
m_2 = \overline{A}\overline{B}C\overline{D},
m_5 = \overline{A}B\overline{C}D,
m_7 = \overline{A}BCD,
m_8 = A\overline{B}\overline{C}\overline{D},
m_{10} = A\overline{B}C\overline{D},
m_{13} = AB\overline{C}D,
m_{15} = ABCD$$
Hence,
$$f = \overline{A}\overline{B}\overline{C}\overline{D} + \overline{A}\overline{B}C\overline{D} + \overline{A}B\overline{C}D + \overline{A}BCD + A\overline{B}\overline{C}\overline{D} + A\overline{B}C\overline{D} + AB\overline{C}D + ABCD$$
2. **Simplify the given logic circuit output X.**
From the problem description, the logic gates invert A, B, C, then use AND, OR gates combining the signals.
Assuming the expression from description:
$$X = [A\overline{B}(C + BD) + A + \overline{B} + \overline{C}]C$$
Simplify inside the bracket first:
- Note that $A + \overline{B} + \overline{C}$ covers many cases, so combined with $A\overline{B}(C+BD)$ it simplifies.
Rewrite:
$$X = [A + \overline{B} + \overline{C}]C$$
Because $A + \overline{B} + \overline{C}$ dominates the other term.
Distribute $C$:
$$X = AC + \overline{B}C + \overline{C}C$$
Note $\overline{C}C=0$,
So,
$$X = AC + \overline{B}C = C(A + \overline{B})$$
This is the simplified Boolean expression.
3. **Perform BCD Addition of A and B:**
Given:
$$A = 0101\ 0110\ 0111 \, (BCD \ digits: 5, 6, 7)$$
$$B = 0011\ 1000\ 1001 \, (BCD \ digits: 3, 8, 9)$$
Add digit by digit (right to left):
- 7 + 9 = 16 decimal (invalid BCD, over 9), So add 6 (0110) to correct:
7 (0111) + 9 (1001) = 16 (10000 binary, 5 bits too large), after adding 0110 (6): 10000 + 0110 = 10110 (22 decimal), take right 4 bits (0110) for digit value 6 and carry 1 to next digit.
- Next digit: 6 + 8 + carry 1 = 15 decimal
15 > 9, add 6:
15 + 6 = 21 decimal
Represented in BCD as carry 1 and digit 5
- Next digit: 5 + 3 + carry 1 = 9 decimal (valid, no correction needed)
Final BCD result:
$$\boxed{1001\ 0101\ 0110}$$
Which is decimal 9 5 6.
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**Summary of answers:**
- SPOS expression for $f$ as above.
- Simplified $X = C(A + \overline{B})$
- BCD addition result = 1001 0101 0110